x^2(b-c)+b^2(c+x)-c^2(x+b)=6

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Solution for x^2(b-c)+b^2(c+x)-c^2(x+b)=6 equation:


Simplifying
x2(b + -1c) + b2(c + x) + -1c2(x + b) = 6
(b * x2 + -1c * x2) + b2(c + x) + -1c2(x + b) = 6
(bx2 + -1cx2) + b2(c + x) + -1c2(x + b) = 6
bx2 + -1cx2 + (c * b2 + x * b2) + -1c2(x + b) = 6
bx2 + -1cx2 + (b2c + b2x) + -1c2(x + b) = 6

Reorder the terms:
bx2 + -1cx2 + b2c + b2x + -1c2(b + x) = 6
bx2 + -1cx2 + b2c + b2x + (b * -1c2 + x * -1c2) = 6
bx2 + -1cx2 + b2c + b2x + (-1bc2 + -1c2x) = 6

Reorder the terms:
-1bc2 + bx2 + b2c + b2x + -1cx2 + -1c2x = 6

Solving
-1bc2 + bx2 + b2c + b2x + -1cx2 + -1c2x = 6

Solving for variable 'b'.

Reorder the terms:
-6 + -1bc2 + bx2 + b2c + b2x + -1cx2 + -1c2x = 6 + -6

Combine like terms: 6 + -6 = 0
-6 + -1bc2 + bx2 + b2c + b2x + -1cx2 + -1c2x = 0

The solution to this equation could not be determined.

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